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Re: POA (King's Dilemma)
Posted By: mandichaos, on host 68.55.86.54
Date: Tuesday, December 30, 2003, at 16:50:14
In Reply To: POA posted by Tungman on Tuesday, December 30, 2003, at 16:39:21:

> I am Sawyers room trying to figure out the combination for his safe,I have never been a maths matical person,so Im not good at understanding these sorts of maths things,can someone please help me here,thanks

Well, I won't spoil it completely, but I will break it down for you. First off, the combination must be a four-digit number. Second off, I'm going to repost the poem that gives you the answer:

"All those gathered, silent, solemn,
Then were ranked by row and column,
Equal numbers to each file.
Though the king tried rows of seven,
Then thirteen, and yes, eleven,
Five were extra, every trial."

Okay, then, this requires a number that's divisible by seven, thirteen, and eleven... with five left over. That's what's tripping you up, right? Got to work backwards.

First, find a number that's divisible by seven, thirteen, and eleven with no remainder. Easiest way to do this:

7 x 13 x 11 = first number

This number is not the answer, but it's the first step. You may notice that this first number is NOT divisible by 5, which we also need:

"Sighing deeply in frustration,
Tried one final combination,
Found success in rows of five."

BINGO. This number needs to be divisible by 5 as well! So we do this:

first number x 5 = second number

However, there's one more thing: that remainder of five. This number is evenly divisible by 7, 11, and 13. We don't want that, but we need to keep it divisible by 5. How?

second number + 5 = the combination

That should do it!

-Mandi aka Chaos